上 (x-2)^2 (y 1)^2=9 graph 225768-Which graph most closely represents (x+2)2+(y+1)2=9

Y= (1/2) (x1/2)^29/8 This is an equation of a parabola that opens upwards Its standard form of equationy=A (xh)^2k, (h,k)= (x,y) coordinates of the vertex for given equationy= (1/2) (x1/2)^29/8 vertex (1/2,9/8) see graph below(e) Below is the graph of z = x2 y2 On the graph of the surface, sketch the traces that you found in parts (a) and (c) For problems 1213, nd an equation of the trace of the surface in the indicated plane Describe the graph of the trace 12 Surface 8x 2 y z2 = 9;1) y = 2(x 2)^2 2 2) y = (x 2)^2 2 3) y = (x 2)^2 2 4) y = (x 2)^2 2 the answers to ihomeworkhelperscom

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Which graph most closely represents (x+2)2+(y+1)2=9- Answer 2 📌📌📌 question What is the slope of the line on the graph?Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more

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 The graph of y=x^2 is reflected in the xaxis, then stretched vertically by a factor of 2, and then translated 3 units to the left and 1 unit down I need to write the equation of this parabola in standard and general form I have MATH (Please) Show all the steps that you use to solve this problemBecause there are 2 ellipsoid graphs to choose from, we look at the major axis in the function and pick the graph with the corresponding major axis x axis radius = (sqrt(1/9))^2, y axis radius = (sqrt(1/4))^2 z axis radius = 1 We see the major axis is the Z axis, and the corresponding graph is IV This is graph IV🔴 Answer 2 🔴 on a question Which equation is correct for the graph shown?

You can put this solution on YOUR website! This comes from #sqrt(4)# that is the denominator of the #x^2# term Then, go up and down 3 units (#sqrt(9)#) to find corners of a "box" that will create asymptotes for your shape The slopes of the asymptotes will be #3/2# for these reasons This graph was created in TInspire, with a template for graphing the conic sections and other relations x^2 xy y^2 = 9 2x x dy/dx y 2y dy/dx = 0 dy/dx(x 2y)= 2x y) dy/dx = (2xy)/(x2y) < you had that, good!

3 must be factored from 3x2 9x x must be factored from 3x2 9x 9 must be factored from 9x 18 3 must be factored from 3x2 18 A Which phrase best describes the translation from the graph y = 6x2 to the graph of y = 6 (x 1)2?Sin (x)cos (y)=05 2x−3y=1 cos (x^2)=y (x−3) (x3)=y^2 y=x^2 If you don't include an equals sign, it will assume you mean " =0 " It has not been well tested, so have fun with it, but don't trust it If it gives you problems, let me know Note it may take a few seconds to finish, because it has to do lots of calculationsProblem 1 Easy Difficulty Sketch the graph of the cylinder in an x y z − coordinate system x 2 y 2 = 9

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 A circle with a radius of 3, and its center located at (4,1) Given (x4)^2(y1)^2=9 Notice that the equation for a circle is given by (xa)^2(yb)^2=r^2 where (a,b) are the coordinates of the circle's center r is the radius of the circle Here, we get (a,b)=(4,1), and 9=3^2Graph (x1)^2 (y2)^2=9 (x − 1)2 (y 2)2 = 9 ( x 1) 2 ( y 2) 2 = 9 This is the form of a circle Use this form to determine the center and radius of the circle (x−h)2 (y−k)2 = r2 ( x h) 2 ( y k) 2 = r 2 Match the values in this circle to those of the standard formTo have a vertical tangent, the denominator of the above has to be zero, that is, dy/dx must be undefined x2y = 0 x = 2y sub into the original (2y)^2 (2y)(y) y^2 = 9 4y^2 2y^2 y^2 = 9 3y^2 = 9 y^2 = 3 y = ± ?3 when y = ?3, x = 2?3

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Circle on a Graph Let us put a circle of radius 5 on a graph Now let's work out exactly where all the points are We make a rightangled triangle And then use Pythagoras x 2 y 2 = 5 2 There are an infinite number of those points, here are some examples x y x 2 y 2;The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction x^ {2}2xy^ {2}2y=0 x 2 2 x y 2 2 y = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 1 for a, 2 for b, and y\left (2y\right) for c in the quadratic formula, \frac {b±\sqrt {b^ {2Y=2(X1)^25 Y=2(X^22X1)5 Y=2X^24X25 Y=2X^24X7 (graph 300x0 pixels, x from 6 to 5, y from 10 to 10, 2x^2 4x 7)

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Use the vertex form, y = a ( x − h) 2 k y = a ( x h) 2 k, to determine the values of a a, h h, and k k a = 1 a = 1 DA 47 PA 7 MOZ Rank 10 Graph y=x^24 MathwayX^2 2 y^2 = 1 Natural Language;Popular Problems Calculus Graph y^2x^2=9 y2 − x2 = 9 y 2 x 2 = 9 Find the standard form of the hyperbola Tap for more steps Divide each term by 9 9 to make the right side equal to one y 2 9 − x 2 9 = 9 9 y 2 9 x 2 9 = 9 9 Simplify each term in the equation in order to set the right side equal to 1 1

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Use a table of values to graph y = 2x24x 1 xy1 6 01 1 2 2 3 3 2 41 x y O Graph the ordered pairs in the table and connect them with a smooth curve b What is the domain and range of this function?(f) Write the domain of q 3 4 6 2 4 (9) Write the range of q 3 6 7 Given the function defined by h (x) = 5, find h (6) Write your answer in exact, simplifiedQuestion The graph of y=9 (x) is given 2 (a) Find 9 (3) (b) Find q (1) (c) Find 7 (1) (d) For what value (s) of x is q (x) = 0?

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Algebra > Quadraticrelationsandconicsections> SOLUTION sketch the graph of each ellipse 1x^2/9y^2/4=1 2x^2/9y^2=1 3x^2y^2/4=1 4y^2/4x^2/25=1 5y^2/9X^2/16=1 6x^2/25y^2=1 7x^2y^2/9=1 8x^2y^2/25=1 9x^2/9y^2=1 Log On5 0 5 2 0 2 = 25 0 = 25 3 4 3 2 4 2 = 9 16 = 25 0 5 0Multiply − 1 1 by 0 0 Add − 9 9 and 0 0 Substitute the values of a a, d d, and e e into the vertex form a ( x d) 2 e a ( x d) 2 e Set y y equal to the new right side Use the vertex form, y = a ( x − h) 2 k y = a ( x h) 2 k, to determine the values of a a, h h, and k k

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$\begingroup$ How did you get negative 1/2 if one divides both sides by 2 to get rid of the 2 that is adjacent to the quantity (y1)^2?Graph {eq}(x 2)^2 (y 1)^2 = 9 {/eq} Circles A circle is a two dimensional relationship for which every point is equally distant from the point in the centerFind stepbystep Calculus solutions and your answer to the following textbook question Suppose the line tangent to the graph of f x=2 is y=4x1 and suppose y=3x2 is the line tangent to the graph of g at x=2 Find an equation of the line tangent to the following curves at x=2 a y=f(x)g(x), b y=$\frac { f ( x ) } { g ( x ) }$

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A circle is all points in a plane that are a fixed distance from a given point on the plane The given point is called the center, and the fixed distance is called the radius The standard form of the equation of a circle with center (h,k) ( h, k) and radius r r is (x−h)2(y−k)2 = r2 ( x − h) 2 ( y − k) 2 = r 2Answer (1 of 6) That's a circle Compare x^2y^22x=0 with the general equation of a circle x^2y^22gx2fyc=0 and write down the values of the constants g, f and c g=1 f=0 c=0 The centre of the circle is (g,f)\equiv(1,0) The radius of the circle is \sqrt{g^2f^2c}=\sqrt{1} IfGraph x^2=y^2z^2 Natural Language;

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 You find the centre, the vertices, and the endpoints of the function Then you plot the graph (x1)^2 (y4)^2 = 9 This is the standard form for the equation of a circle with centre at (1,4) and radius sqrt9 = 3 This means that, to find the vertices, you go 3 units up from the centre and 3 units down Thus, the vertices are at (1,7) and (1,1)X 2 4 y 2 9 z 2 = 1 Multiply both sides of the equation by 36, the least common multiple of 4,9 Multiply both sides of the equation by 3 6, the least common multiple of 4, 9 36x^ {2}9y^ {2}4z^ {2}=36 3 6 x 2 9 y 2 4 z 2 = 3 6 Subtract 9y^ {2} from both sides Subtract 9 y 2Graph y=2(x1)^25 Answer by checkley71(8403) (Show Source) You can put this solution on YOUR website!

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Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, musicAs you can see, this graph is of 2 parallel lines This is because the equation x 2 2xy y 2 = 9 can be factored into (xy)(xy) = 9 which is equivalent to (xy) 2 = 9 Then, to simplify this equation, take the square root of both sides and you get two different equations x y = 3 and x y = 3Or are you doing something else?

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How do you graph y=x2Video instruction on how to graph the equation y=x2 how do you graph y=x2Video instruction on how to graph the equation y=x2(e) For what value (s) of x is q (x)= 2?Graph the parabola, y =x^21 by finding the turning point and using a table to find values for x and y

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Answer (1 of 3) The same way you plot anything Even with this equation being complicated looking, just assume that this elliptical mapping has some yvalue(s) for whatever xvalue(s) Since this is second order, we can expect it to have some values So, start off by making a list When x=0, yDescription Function Grapher is a full featured Graphing Utility that supports graphing up to 5 functions together You can also save your work as a URL (website link) Usage To plot a function just type it into the function boxFree graphing calculator instantly graphs your math problems

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Figure 275 In threedimensional space, the graph of equation x 2 y 2 = 9 x 2 y 2 = 9 is a cylinder with radius 3 3 centered on the zaxis It continues indefinitely inPlane z = 1 The trace in the z = 1 plane is the ellipse x2 y2 8 = 1, shown below 6Graph the ellipse and its foci x^2/9 y^2/4=1 standard forms of ellipse (xh)^2/a^2(yk)^2/b^2=1 (horizontal major axis),a>b (yk)^2/a^2(xh)^2/b^2=1 (vertical major axis),a>b given ellipse has horizontal major axis center(0,0) a^2=9 a=3 b^2=4 b=2 c=sqrt(a^2b^2)=sqrt(94)=sqrt(5)=224 foci=(224,0),(224,0) see graph of given

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The domain (the xvalues) is all real numbers The range (the yvalues) is allUse the center, vertices, and asymptotes to graph the hyperbola (x 1)^2 9(y 2)^2 = 9 (x1)^2/9 (y2)^2 = 1 This is aExtended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music

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Steps to graph x^2 y^2 = 4Trigonometry Graph (x^2)/9 (y^2)/1=1 x2 9 − y2 1 = 1 x 2 9 y 2 1 = 1 Simplify each term in the equation in order to set the right side equal to 1 1 The standard form of an ellipse or hyperbola requires the right side of the equation be 1 1 x2 9 − y2 1 = 1 x 2 9Y x x 2 2 1 Example • Use characteristics of quadratic functions to graph – Find the equation of the axis of symmetry – Find the coordinates of the vertex of the parabola – Graph the function y parent graph of y = x2 Then name the vertex ( 2) 1 ( 7) 2 ( 2) 6 2 2 2 2 2

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Graph the parent quadratic (y = x^2) by creating a table of values using select x values The graph of this parent quadratic is called a parabolaNOTE Any6 unit left 6 unit right 1 unit leftDivide 2, the coefficient of the x term, by 2 to get 1 Then add the square of 1 to both sides of the equation This step makes the left hand side of the equation a perfect square x^ {2}2x1=\frac {y1} {3}1 Square 1 x^ {2}2x1=\frac {y2} {3} Add \frac {y1} {3} to 1 \left (x1\right)^ {2}=\frac {y2

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